Which students line segments have a midpoint of (-1,4)? Select all that apply A. Student 1 B. Student 2 C. Student 3 D. Student 4 E. Student 5

Answer:
C. Student 3
E. Student 5
Step-by-step explanation:
we know that
The formula to calculate the midpoint between two points is equal to
[tex]M(\frac{x1+x2}{2},\frac{y1+y2}{2})[/tex]
Verify the midpoint of each student
student 1
we have the endpoints
(-9,0) and (11,-8)
substitute in the formula
[tex]M(\frac{-9+11}{2},\frac{0-8}{2})[/tex]
[tex]M(1,-4)[/tex]
so
The midpoint is not (-1,4)
student 2
we have the endpoints
(-6,-1) and (4,-7)
substitute in the formula
[tex]M(\frac{-6+4}{2},\frac{-1-7}{2})[/tex]
[tex]M(-1,-4)[/tex]
so
The midpoint is not (-1,4)
student 3
we have the endpoints
(-5,2) and (3,6)
substitute in the formula
[tex]M(\frac{-5+3}{2},\frac{2+6}{2})[/tex]
[tex]M(-1,4)[/tex]
so
The midpoint is equal to (-1,4)
student 4
we have the endpoints
(-3,10) and (5,-2)
substitute in the formula
[tex]M(\frac{-3+5}{2},\frac{10-2}{2})[/tex]
[tex]M(1,4)[/tex]
so
The midpoint is not (-1,4)
student 5
we have the endpoints
(0,-3) and (-2,11)
substitute in the formula
[tex]M(\frac{0-2}{2},\frac{-3+11}{2})[/tex]
[tex]M(-1,4)[/tex]
so
The midpoint is equal to (-1,4)
therefore
Student 3 and student 5