A) Car A is traveling at the greatest speed.
Step-by-step explanation:
Step 1:
For car A, we determine a value that coincides with both an x and a y value. (5, 150) is such a point.
So if car A travels 150 miles in 5 hours, car A covers 30 miles in an hour.
For car B, [tex]y =12.5 x,[/tex] where y is the distance in miles and x is the time taken.
If [tex]x=1, y = 12.5(1) = 12.5.[/tex] If [tex]x=2, y = 12.5(1) =25.[/tex]
So car B travels [tex]25 -12.5 =12 .5[/tex] miles every hour.
Step 2:
For car C, [tex]y =20 x,[/tex] where y is the distance in miles and x is the time taken.
If [tex]x=1, y = 20(1) = 20.[/tex] If [tex]x=2, y = 20(1) =40.[/tex]
So car C travels [tex]40 - 20 = 20[/tex] miles every hour.
For car D, [tex]y =25 x,[/tex] where y is the distance in miles and x is the time taken.
If [tex]x=1, y = 25(1) = 25.[/tex] If [tex]x=2, y = 25(1) =50.[/tex]
So car D travels [tex]50 -25 =25[/tex] miles every hour.
Step 3:
Car A travels at a speed of 30 miles per hour, Car B travels at a speed of 12.5 miles per hour, Car C travels at a speed of 40 miles per hour and Car D travels at a speed of 25 miles per hour.
So car A is traveling at the greatest speed which is option A.
