Respuesta :

BlackBull
Table A is easy: y = x;

Table B:
Y = kx + b;

When x = 6, y = 0;
When x = 4, y = 1;

System:
6k + b = 0;
4k + b = 1;
———————
Subtract:
2k = -1;
k = -1/2;

-1/2 * 6 + b = 0;
-3 + b = 0;
b = 3;

So Table B: Y = (-1/2)x + 3;
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