Answer:
[tex]M_{base}=0.14M[/tex]
Explanation:
Hello,
In this case, the first step is to compute the oxalic acid dihydrate's moles as shown below, considering its molar mass as 126 g/mol:
[tex]n_{acid}=\frac{0.647g}{126 g/mol} =0.00513mol[/tex]
Now, since the undergoing chemical reaction is:
[tex]Ba(OH)_2+H_2C_2O_4\rightarrow BaC_2O_4+2H_2O[/tex]
Their molar relationship is 1 to 1, therefore:
[tex]n_{acid}=n_{base}[/tex]
Thus, the barium hydroxide's molarity turns out:
[tex]M_{base}=\frac{0.00513mol}{0.0359L}=0.14M[/tex]
Best regards.
