Estimate the average power output of the Sun, given that about 1350 W/m2 reaches the upper atmosphere of the Earth. Express your answer with the appropriate units. S = nothing nothing

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Answer:

The average power output of the Sun will be 3.8 × [tex]10^{26}[/tex] W.

Explanation:

The intensity falling over a surface area is defined as Energy falling per unit area per unit volume, i.e,

I = [tex]\frac{Energy}{Area\times Time }[/tex]

Also, Power, P = Energy/time

So, Intensity = Power/ Area

or, Power = Intensity × Area

Now, Distance from Sun to Earth , r = 149.6 × [tex]10^{9}[/tex] m

So, Surface area of the sphere of radius r will be:-

A = 4 π [tex]r^{2}[/tex]

  = 4 × 3.14 × (149.6 × [tex]10^{9}[/tex])²

  =  2.81 × [tex]10^{23}[/tex] m²

Thus Average Power will be:

P = 1350 × 2.81 × [tex]10^{23}[/tex]

 = 3.7935 × [tex]10^{26}[/tex]

 = 3.8 × [tex]10^{26}[/tex] W

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