Answer:
Step-by-step explanation:
In this case the solution of the integral is
[tex]\int\limits^{2\pi} _0 {} \, d\phi \int\limits^R_0 {\rho}h \, d\rho = [2\pi - 0](\frac{1}{2} )[R^{2} - 0]h = \pi R^{2}h[/tex]
because h is a constant, and where the expression
[tex]\int {\rho} \, d\rho = \frac{\rho^{2}}{2}[/tex]
was used.
I hope this is usefull for you
regards.
