Answer:
NaOH → 0.015 M
Explanation:
We propose the neutralization formula to solve the problem:
N acid . Volume acid = N base . Volume base
N means normality. A sort of concentration that is defined as:
M / val where the val means the number of H⁺ and OH⁻ from the acid or the base.
In this case, we have NaOH and HCl, so the M = N
Let's replace data:
0.01 M . 22.4 mL = 15 mL . M NaOH
0.01 M . 22.4 mL / 15 mL = M NaOH → 0.015 M
