Answer:
225.4 m
Explanation:
We are given that
Mass =m=49 kg
a.Speed,v=94 m/s
We have to find the minimum radius of the circle for the acceleration at this point not to exceed 4 g.
We know that
Radial acceleration,[tex]a=\frac{v^2}{R}[/tex]
Using the formula
[tex]4g=\frac{(94)^2}{R}[/tex]
[tex]R=\frac{(94)^2}{4g}[/tex]
We know that g=[tex]9.8m/s^2[/tex]
[tex]R=\frac{(94)^2}{4\times 9.8}[/tex]
[tex]R=225.4 m[/tex]
