Answer:
Option B)
y to the [tex]2^{nd}[/tex] power - [tex]\frac{28}{7}[/tex]
Step-by-step explanation:
We are given the following in the question:
"the square of y decreased by the quotient of 28 and 7"
We can write this in the form of expression as:
[tex]y^2 - \dfrac{28}{7}\\\\=y^2 - 4[/tex]
Thus, the correct expression is given by
Option B)
y to the [tex]2^{nd}[/tex] power - [tex]\frac{28}{7}[/tex]
