Answer:
The electric potential difference between two given points is [tex]0.6KV[/tex]
Explanation:
Here we know that work done by electrostatic force = change in its kinetic energy
work done= [tex]4.8J[/tex]
since Δv =[tex]V_{B}-V_{A}[/tex] = [tex]\frac{-work \, done \, by \, electrostaticforce}{charge}[/tex]
Δv =[tex]V_{B} -V_{A}[/tex]= [tex]\frac{-4.8}{-8\times 10^{-3}}[/tex] = [tex]0.6KV[/tex]
