Answer:
0.00147 Molar is the molarity of the solution.
Explanation:
Molarity of the solution is the moles of compound in 1 Liter solutions.
[tex]Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}[/tex]
Mass of calcium sulfate = 0.03 g
Molar mass of calcium sulfate = 136 g/mol
Volume of the calcium sulfate = 150. mL = 0.150 L ( 1 L = 0.001 mL)
[tex]Molarity=\frac{0.03 g}{136 g/mol\times 0.150 L}=0.00147 mol/L[/tex]
0.00147 Molar is the molarity of the solution.
