Answer : The final pressure of the gas will be, 1.5 atm
Explanation :
Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.
[tex]P\propto T[/tex]
or,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 1.2 atm
[tex]P_2[/tex] = final pressure of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]25^oC=273+25=298K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]100^oC=273+100=373K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{1.2atm}{298K}=\frac{P_2}{373K}[/tex]
[tex]P_2=1.5atm[/tex]
Thus, the final pressure of the gas will be, 1.5 atm
