The body temperatures of adults have a mean of 98.6°F and a standard deviation of 0.60° F. Describe the center and variability of the sampling distribution of the sample mean for a random sample of 50 adults. center = 98.6, variability = 0.14 center = 98.6, variability = 0.07 center = 0.60, variability = 0.07 center = 98.6, variability = 0.008 center = 98.6, variability = 0.08

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Answer:

center = 98.6, variability = 0.08

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sample means with size n of at least 30 can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

The center is the mean.

So [tex]\mu = 98.6[/tex]

The standard deviation of the sample of 50 adults is the variability, so

[tex]s = \frac{0.6}{\sqrt{50}} = 0.08[/tex]

So the correct answer is:

center = 98.6, variability = 0.08

The center is 98.6 and the variability is 0.08.

Central Limit Theorem:

Since The body temperatures of adults have a mean of 98.6°F and a standard deviation of 0.60° F.

The Central Limit Theorem developed that for a random variable X along with mean and standard deviation, the sample should be with size n of at least 30 can be expected to a normal distribution along with mean and standard deviation.

Now here the center should be equivalent to the mean i.e. 98.6

And, the variability is [tex]= {0.6}\div \sqrt50[/tex]

= 0.08

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