Answer:
We will need 3 Liters of 40% solution and 9 Liters of 20% solution to add together to get the required solution.
Explanation:
Let the volume of 40% of brine solution be x and volume of 20% of brine solution be y.
Volume of brine solution in 40% solution = 40% of x = 0.4x
Volume of brine solution in 20% solution = 20% of y = 0.2y
Percentage of brine solution required = 25%
Total volume of brine solution of 25% required = 12 L
x + y = 12 L...[1]
[tex]0.4x+0.2y=\frac{25}{100}\times 12[/tex]
[tex]0.4x+0.2y=3[/tex]..[2]
Solving [1] and [2]: we get :
x = 3
y = 9
We will need 3 Liters of 40% solution and 9 Liters of 20% solution to add together to get the required solution.
