Respuesta :
Answer:
943 Nm/C
Explanation:
Parameters given:
Radius of sphere, r = 0.23 m
Field at the surface of sphere, E = 4100 N/C
Electric potential is given as:
V = E * r
The electric potential at the center of the sphere will be the product of electric field at the center and the distance between the surface and center (radius).
V = 4100 * 0.23
V = 943 Nm/C
Given Information:
Electric field = E = 4100 N/C
Radius of sphere = r = 0.230 m
Required Information:
Potential = V = ?
Answer:
Potential = 9.43×10² Volts
Explanation:
The relation between electric field and potential is given by
V = Er
Where E is the electric field at the surface of charged sphere and r is the radius of sphere
V = 4100*0.230
V = 9.43×10² N.m/C
1 Volt is equal to 1 N.m/C
V = 9.43×10² Volts
Therefore, the potential at the center of the sphere is 9.43×10² Volts.
