A coffee pot in the form of a circular cylinder of radius 2 in. is being filled with water flowing at a constant rate. If the water level is rising at the rate of 0.2 in./sec, what is the rate at which water is flowing into the coffee pot

Respuesta :

Answer:

The rate at which water flowing is 0.04116 liter per second

Explanation:

we know that the rate at which water is flowing into pot is equal to the amount of water flowing into pot per second .

⇒Volume of water entering per second = [tex]\frac{area\times length}{time}=area\times the \: rate \: of \: water \;level \: raising[/tex]

area = [tex]\pi r^{2}[/tex]

given that r= [tex]2in[/tex]

⇒ This is equal to The rate at which water level is raising ×area of the given pot .

 ⇒0.2×2×2×π cubic inch per second

 ⇒2.515 cubic inch per second

we know that [tex]1[/tex] [tex]in^{3}=0.01638 l[/tex]

 ≡0.04116 liter per second

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