Answer:
In dB intensity will be equal to 159.74 dB
Explanation:
We have given intensity of sound produced by one singer is 76.7 dB
Sound intensity is calculated as [tex]I(dB)=10log\frac{I}{10^{-12}}[/tex]
[tex]76.7=10log\frac{I}{10^{-12}}[/tex]
[tex]10^{7.67}=\frac{I}{10^{-12}}[/tex]
[tex]I=4.677\times 10^{-5}[/tex] [tex]W/m^2[/tex]
Now it is given that 41 singers are singing in chorus
So total intensity = [tex]I=41\times 4.677\times 10^{-5}=191.757\times 10^{-5}W/m^2[/tex]
Now in dB intensity will be
[tex]I(dB)=10log\frac{191.757\times 10^{-5}}{10^{-12}}=159.74dB[/tex]
