Answer:
a) 0.792A
b) 7.0 x 10^7 A/m^2
Explanation:
The explanation is given in the picture below
Answer:
Explanation:
Guven:
Radius of the wire, Radius.w = 1.5/2 mm
= 0.75 × 10^-3 m
Radius of the filament, Radius.f = 0.12/2 mm
= 0.6 × 10^-4 m
Current density of the wire, J = 4.5 × 10^5 A/m^2
Current, I = J × Area.w
= 4.5 × 10^5 × pi × (0.75 × 0^-3)^2
= 0.795 A
= 0.8 A
B.
Area.f = pi × Raduis.f^2
= pi × (0.6 × 10^-4)^2
= 1.13 × 10^-8 m^2
J = I/Area.f
= 0.8/1.13 × 10^-8
= 7.07 × 10^7 A/m^2
