Answer:
147.456077993 Hz
Explanation:
[tex]f_0[/tex] = Frequency of the sonar = 22 kHz
[tex]v_w[/tex] = Velocity of the whale = 4.95 m/s
v = Speed of sound in water = 1482 m/s
The difference in frequency is given by
[tex]\Delta f=f_0\times\dfrac{2v_{w}}{v-v_w}\\\Rightarrow \Delta f=22000\times\dfrac{2\times 4.95}{1482-4.95}\\\Rightarrow \Delta f=147.456077993\ Hz[/tex]
The difference in frequency is 147.456077993 Hz