Answer:
0.5926
Step-by-step explanation:
given that three airlines serve a small town in Ohio. Airline A has 50% of all the scheduled flights, airline B has 30%, and airline C has the remaining 20%
i.e. A,B,C are mutually exclusive and exhaustive events as there is no other flight than these three.
Flight Prob Time rates prob Combined prob
A 0.50 0.80 0.5*0.8 =0.40
B 0.30 0.65 0.3*0.65 = 0.195
C 0.20 0.40 0.2*0.4=0.08
Total = 0.675
A plane has just left on time. What is the probability that it was airline A
= P(A/time) = Pr of time and A/Prob of time
= [tex]\frac{0.4}{0.675} \\=0.5926[/tex]
Answer is 0.5926
