Respuesta :
Answer:
The volume of carbon dioxide at 20.0°C and 0.941 atm produced was 6390.89 Liters.
More volume of carbon dioxide gas was released on combustion of 4.00 kg of propane in comparison to the volume of carbon dioxide released on combustion of 4.00 kg of methane.
Explanation:
Methane
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]
Mass of methane = 4.00 kg = 4000 g (1 kg = 1000 g)
Moles of methane = [tex]\frac{4000 g}{16 g/mol}=250 mol[/tex]
According to reaction, 1 mole of methane gives 1 mole of carbon dioxide gas,then 250 moles of methane will give :
[tex]\frac{1}{1}\times 250 mol=250 mol[/tex] of carbon dioxide gas
Moles of carbon dioxide gas = n = 250 mol
Pressure of carbon dioxide gas = P = 0.941 atm
Temperature of carbon dioxide gas = T = 20.0°C = 20.0+273 K = 293 K
Volume of carbon dioxide gas = V
[tex]PV=nRT[/tex] (Ideal gas equation)
[tex]V=\frac{nRT}{P}=\frac{250 mol\times 0.0821 atm L/mol K\times 293 K}{0.941 atm}=6390.89 L[/tex]
The volume of carbon dioxide at 20.0°C and 0.941 atm produced was 6390.89 Liters.
Propane
[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]
Mass of propane = 4.00 kg = 4000 g (1 kg = 1000 g)
Moles of propane = [tex]\frac{4000 g}{44 g/mol}=90.91 mol[/tex]
According to reaction, 1 mole of propane gives 3 mole of carbon dioxide gas,then 90.91 moles of propane will give :
[tex]\frac{3}{1}\times 90.91 mol=272.73 mol[/tex] of carbon dioxide gas
Moles of carbon dioxide gas = n = 272.73 mol
Pressure of carbon dioxide gas = P = 0.941 atm
Temperature of carbon dioxide gas = T = 20.0°C = 20.0+273 K = 293 K
Volume of carbon dioxide gas = V
[tex]PV=nRT[/tex] (Ideal gas equation)
[tex]V=\frac{nRT}{P}=\frac{272.73 mol\times 0.0821 atm L/mol K\times 293 K}{0.941 atm}=6,971.95 L[/tex]
The volume of carbon dioxide at 20.0°C and 0.941 atm produced was 6,971.95 Liters.
Volume of carbon dioxide given by combustion of 4.00 kg of methane = 6390.89 Liters.
Volume of carbon dioxide given by combustion of 4.00 kg of propane = 6,971.95 Liters.
6390.89 Liters < 6,971.95 Liters
More volume of carbon dioxide gas was released on combustion of 4.00 kg of propane in comparison to the volume of carbon dioxide released on combustion of 4.00 kg of methane.
