Respuesta :
Answer:
Explanation:
The point will lay at x = L/2 ( in the middle)
Let the charge given be Q at x = 0 and L , and q is the charge required.
Force on charge put on x = 0 , due to charge in the middle
k Q q / .5 L
Force on charge put on x = 0 , due to charge at x = L
= k Q q / L
Total force
= k Q q / .5 L + k Q² / L = 0, FOR BALANCE.
2q = - Q
q = - Q / 2
In the middle , half the charge of either of equal charge placed at x = 0 and L should be placed . Its nature negative .
Answer:
Explanation:
Let the two charges is at x = 0 an x = L is Q.
Let the third charge is q placed at x = L/2.
Let the net force on the charge placed at x = 0 is zero.
force on charge Q placed at x = 0 due to the charge Q placed at x = L
[tex]F_{1}=\frac{KQ^{2}}{L^{2}}[/tex]
force on charge Q placed at origin due to charge q placed at x = L/2
[tex]F_{2}=\frac{4KQq}{L^{2}}[/tex]
As the net force on the charge at x = 0 is zero so
F1 = F2
[tex]\frac{KQQ}{L^{2}}=\frac{4KQq}{L^{2}}[/tex]
Q = 4 q
q = Q / 4
Charge q should be negative in nature as the system of charges is in stable equilibrium.
In the middle , half the charge of either of equal charge placed at x = 0 and L should be placed . Its nature negative .
