Sally has $200 in her savings account last month. She added $35 this month and earned $0.75 interest. What is the percent of the increase in the amount in her savings account to the nearest tenth percent? *

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Answer:

The percentage increase in the amount in her savings is 17.9%

Step-by-step explanation:

The formula for percentage increase is given as,  

[tex]Percentage\:Increase=\dfrac{New\:Value-Old\:Value}{Old\:Value}[/tex]

In previous month, amount of saving in Sally’s account was $200.  

In the current month she added $35 and earned an interest of $0.75. So the total earning in current month will be,  

Total earning = Amount in previous month + Amount added + Interest earned  

Total earning = $ 200 + $ 35 + $ 0.75  

Total earning = $235.75

So, current month amount of saving in account is $ 235.75 which becomes new value and previous month balance that is $ 200 becomes old amount.  

Therefore, New value = $ 235.75 and Old value = $ 200  

Substituting the values in the formula,  

[tex]Percentage\:Increase=\dfrac{235.75-200}{200}[/tex]

[tex]Percentage\:Increase=\dfrac{35.75}{200}[/tex]

[tex]Percentage\:Increase=0.17875 [/tex]

[tex]Percentage\:Increase=17.875 [/tex]

Rounding to nearest tenth means one digit after the decimal place. So, percentage increase is 17.9 %

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