Respuesta :
Answer:
cis-hex-2-ene as produced as major product.
Explanation:
- In presence of [tex]Pd/BaSO_{4}[/tex] (Lindlar catalyst) and [tex]H_{2}[/tex], alkynes are reduced to alkene.
- [tex]H_{2}[/tex] molecules first adsorbed onto metal surface through chemisorption.
- When alkyne molecule comes in close proximity to the metal surface, H atoms add onto triple bond to reduce it to alkene.
- Two H atoms add onto alkyne from same face of metal. So, (Z) or cis-isomer of alkene is produced as a major product.
- Reaction mechanism has been shown below.

The reaction of 3-hexyne with hydrogen (1 mol), Lindlar palladium, will result in Z- 3,4 dimethyl hex -3- ene as the major product.
The Lindlar catalyst has been the palladium deposited over the surface of barium sulfate or calcium carbonate. The catalyst has been the compound that does not get utilized in the reaction but helps in increasing the rate of reaction.
Lindlar catalyst helps in the reduction of alkynes to alkenes.
The reaction has been carried forward by the deposition of the alkyne onto the surface of the catalyst. The H atoms from the surface add to the triple bond converting it to alkenes.
The reaction of 3-hexyne with Lindlar catalyst will add the H atoms to the molecule with the same face. The resultant will be the z or cis 3,4 dimethyl hex -3- ene.
The attachment shows the structure of the major compound formed from 3-hexyne.
For more information about Lindlar palladium, refer to the link:
https://brainly.com/question/18851089
