Answer:
The average induced emf = 2.4015V
Explanation:
Given.
Turn, N = 1247
diameter coil = 20cm
Magnetic field = 6.13 * 10^-5T
Parallel to field = 10ms
From Faraday law, we know that the emf induced in a coil is directly proportional to the rate of change of magnetic flux through the coil.
This is given by;
-Nd∅b/ft
= -N * d/dt(BA)
= -NB*dA/dt
= - 1247 * 6.13 * 10^-5 * (0 - (π * 0.10²))/0.001
= 2.40146798192322743920646
= 2.4015V ---- Approximated
The average induced emf = 2.4015V