Answer:
The magnitude of average force [tex]F_{avg} =[/tex] [tex]9.125 \times 10^{4} N[/tex]
Explanation:
Given :
Mass of person [tex]m = 73[/tex] Kg
Initial velocity of car [tex]v_{o} = 20 \frac{m}{s}[/tex]
Average distance [tex]x = 0.16[/tex] m
According to the second law of newton.
[tex]F_{avg} = m a[/tex]
From the kinematic equations,
[tex]v^{2}- v_{o} ^{2} = 2ax[/tex]
Where [tex]v_{o} =[/tex] initial velocity, in our case final velocity is zero ([tex]v = 0[/tex])
[tex]a =- \frac{400}{2 \times 0.16} = -1250 \frac{m}{s^{2} }[/tex]
So average force is given by,
[tex]F _{avg} = 73 \times -1250 = -91250[/tex] N
But magnitude of average force is,
[tex]F_{avg} = 9.125 \times 10^{4}[/tex] N
