Answer:
134F
Step-by-step explanation:
Let C represent temperature and t represent number of hours.
We have been given that the temperature dropped 11 F per hour from the original temperature. So temperature dropped in t hours would be [tex]-11t[/tex].
We will represent our given equation in slope-intercept form:
[tex]C=-11t+b[/tex], where b is initial temperature of compound.
We have been given that after 4 hours, the temperature was 90 F. This means point [tex](4,90)[/tex] in on the line. So we will get:
[tex]90=-11(4)+b[/tex]
[tex]90=-44+b[/tex]
[tex]90+44=-44+44+b[/tex]
[tex]134=b[/tex]
Therefore, the original temperature of the compound is 134F.
