Answer:
Therefore the final temperature of the mixture will be 43.22°C
Explanation:
Density is given as a function of mass in a given volume, mathematically it can be expressed as
[tex]\rho = \frac{m}{V}[/tex]
Where,
m = mass
V = Volume
we have,
[tex]m = \rho V[/tex]
For state 1
we have that the mass is
[tex]m_1 = (1000kg/m^3)(0.361m^3) = 361kg[/tex]
For state 2
[tex]m_2 = (1000kg/m^3)(0.127m^3) = 127kg[/tex]
from calorimetry we know that heat change is given under
[tex]Q = mc_p\Delta T[/tex]
For energy conservation then,
[tex]m_1c_p\Delta T = m_2c_p\Delta T[/tex]
Since the specific heat is the same for the fluid then,
[tex]m_1\Delta T = m_2\Delta T[/tex]
[tex](361) (T-25\°C) = (127) (95\°C-T)T = 43.22\°C[/tex]
Therefore the final temperature of the mixture will be 43.22°C
