Answer:
Estimated Answer=[tex]\frac{1}{2} hour[/tex]
Exact Answer= [tex]\frac{49}{101} hr[/tex]
Step-by-step explanation:
Steady speed of the object =10 and one tenth km/h = [tex]10\frac{1}{10} km/hr[/tex]
Distance to be Covered=4 and nine tenths km =[tex]4\frac{9}{10}[/tex] km
To the nearest integer,
Steady speed of the object = 10 km/hr
Distance=5km
[tex]Time Taken = \frac{Distance}{Average Speed}[/tex]
=[tex]=\frac{5}{10} =\frac{1}{2} hr[/tex]
The estimated answer is 1/2 hr.
Next, we determine the exact answer.
[tex]Time Taken = \frac{Distance}{Average Speed}\\ = 4\frac{9}{10} \div 10\frac{1}{10}\\=\frac{49}{10} \div \frac{101}{10}\\=\frac{49}{10} X \frac{10}{101}\\=\frac{49}{101} hr[/tex]
The exact time taken is [tex]\frac{49}{101} hr[/tex]
