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Work Shown:
Let's make point Q to be at 0 on the number line. The distance from P (-50) to Q (0) is 50 units. The distance from Q to R (50) is also 50 units. These distances add to 50+50 = 100.
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Alternative method:
You can subtract the coordinates of P and R, and then use absolute value to ensure the result is positive
|P - R| = |-50 - 50| = |-100| = 100
or
|R - P| = |50 - (-50)| = |50 + 50| = |100| = 100
Either way, the answer is 100