Answer:
9.2 L is the average volume should the chemical engineer report.
Explanation:
Volume of pollutant from Cross creek plants 10.88 L
Volume of pollutant from Oglala plants = 0.92 L
Volume of pollutant from Platte plants = 15.82 L
Average volume pollutants will be given by :
[tex]=\frac{10.88 L+0.92 L+15.82 L}{3}=9.2067 L\approx 9.2 L[/tex]
9.2 L is the average volume should the chemical engineer report.