Answer: THERE ARE 6 POSSIBLE PAIRING.
Explanation:
There 6 wires and all the possible combinations want to be tested, of 5 of these at a time.
order, or arrangement of the wires within each set of 5 is not important.
By using the combination formula.
c(n,x) = n! / (x! * (n-x)!)
n = 6
x = 5
formula becomes c(6,5) =6!/5!*(6-5)!
= 6! / (5! * 1!)
=6!/5!
=720/120
=6
result is c(6,5) = 6 different test would be required to get all possible combinations of 5 wires each, where order within each set of 5 is not important.
c(6,5) = 8! / (3! * 5!) = 6 possible sets of 5 wires where order within each set of 5 is not important.
