Answer:
The molarity of the chromium(III) acetate solution 0.3982 M.
0.3982 M is the concentration of the chromium(III) cation.
1.1946 M is the concentration of the acetate anion.
Explanation:
[tex]Molarity=\frac{\text{Mass of substance}}{\text{Molar mass of substance}\times \text{Volume of solution(L)}}[/tex]
Mass of chromium(III) acetate = 22.8 g
Molar mass of chromium(III) acetate = 229 g/mol
Total volume of the solution of chromium(III) acetate = V = 250 mL = 0.250 L
1 mL = 0.001 L
The molarity of the chromium(III) acetate solution :
[tex][Cr(CH_3COO)_3]=\frac{22.8 g}{229 g/mol\times 0.250 L}=0.3982 M[/tex]
The molarity of the chromium(III) acetate solution 0.3982 M.
[tex]Cr(CH_3COO)_3\rightarrow Cr^{3+}+3CH_3COO^-[/tex]
According to reaction, 1 mole of chromium(III) acetate gives 1 mole of chromium(III) ions and 3 moles of acetate ions.
So [tex][Cr^{3+}]=[Cr(CH_3COO)_3]=0.3982 M[/tex]
[tex][CH_3COO^-]=3\times [Cr(CH_3COO)_3]=3\times 0.3892 M=1.1946 M[/tex]
0.3982 M is the concentration of the chromium(III) cation.
1.1946 M is the concentration of the acetate anion.
