Answer:
Charge on the other particle is given as
[tex]q_2 = 1.74 \times 10^{-18} C[/tex]
Explanation:
As we know that the force between two charges is given as
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
here we know that
[tex]F = 7 N[/tex]
[tex]r = 0.31 \mu m[/tex]
[tex]q_1 = 4.3 \times 10^{-5} C[/tex]
now we have
[tex]7 = \frac{9 \times 10^9 (4.3 \times 10^{-5}q_2}{(0.31\times 10^{-6})^2}[/tex]
now we have
[tex]q_2 = 1.74 \times 10^{-18} C[/tex]
