Probability of not getting 6 in first roll and getting 6 in second roll is [tex]\frac{5}{36}[/tex]
If the incidence of one event does not affect the probability of the other event then the events are independent of each other and called independent events.
Here the die are fair and loaded.
The gambler selects one die from two die at random and rolls the selected die twice.
The outcomes of the two rolls are independent of each other.
The first outcome is other than 6 and the second outcome is a 6.
Y is a event in which two rolls of the die result in the first roll not coming up 6 and the second roll coming up 6.
The possibilities that the first roll not coming up 6 and the second roll coming up 6 are (1,6), (2,6), (3,6), (4,6), (5,6)
Total number of outcomes is 36.
∴ Probability of not getting 6 in first roll and getting 6 in second roll, i.e. P(Y) = [tex]\frac{5}{36}[/tex]
Learn more about Gambler's problem here :
https://brainly.com/question/15210989
#SPJ2
