A sample of gas occupies a volume of 60.7 mL . As it expands, it does 145.0 J of work on its surroundings at a constant pressure of 783 Torr . What is the final volume of the gas?

Respuesta :

Answer: The final volume of the gas is 1.45 L

Explanation:

To calculate the amount of work done for an isothermal process is given by the equation:

[tex]W=-P\Delta V=-P(V_2-V_1)[/tex]

W = amount of work done  = -145.0 J = 1.431 L.atm   (Conversion factor:  1 L.atm = 101.33 J)  

For expansion, work done is always negative

P = pressure  = 783 Torr = 1.03 atm       (Conversion factor:  1 atm = 760 torr)  

[tex]V_1[/tex] = initial volume  = 60.7 mL = 0.0607 L     (Conversion factor:  1 L = 1000 mL)  

[tex]V_2[/tex] = final volume = ?

Putting values in above equation, we get:

[tex]-1.431L.atm=-(1.03atm)\times (V_2-0.0607)\\\\V_2=1.45L[/tex]

Hence, the final volume of the gas is 1.45 L

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