Answer:
a) YES, this is a minimum standard reduction potential and [tex]E^0_{cathode}= 1.93 V[/tex]
b) NO maximum reduction potential of half cell of cathode.
Explanation:
Given that the galvanic cell must provide at least 1.30 V of electrical power . that denotes that [tex]E^0_{cell} =1.30 V[/tex]
Here, the standard reduction potential of the half-cell reaction of anode is + 0.63 V
i.e [tex]E^0_{anode} = +0.63 V[/tex]
We know that:
[tex]E^0_{cell} = E^0_{cathode}-E^0_{anode}[/tex]
[tex]1.30 V= E^0_{cathode}-(+0.63)V[/tex]
[tex]-E^0_{cathode}= - 1.3 V - 0.63 V[/tex]
[tex]E^0_{cathode}= 1.30 V +0.63 V[/tex]
[tex]E^0_{cathode}= 1.93 V[/tex]
If [tex]E^0_{cathode} > 1.93 V[/tex]; then [tex]E^0_{cell}[/tex] > 1.30 V
Also; If [tex]E^0_{cathode} < 1.93 V[/tex]; then [tex]E^0_{cell}<[/tex] 1.30 V
This is because the cell supply minimum electrical power that is 1.30 V , Hence reduction potential of half- cell reaction at cathode will be minimum at 1.93 V
Therefore, from the foregoing, we conclude that: YES, this is a minimum standard reduction potential.
[tex]E^0_{cell} = E^0_{cathode}-E^0_{anode}[/tex]
[tex]E^0_{cell} = E^0_{cathode}-(+0.63V)[/tex]
So, if reduction potential value of the half-cell reaction used at cathode is greater than 1.93 (V); we get at least 1.30 V or greater than 1.30 V cell emf.
As such, No maximum reduction potential of half cell of cathode.
