Answer:
Molarity =7.3 M
H₂SO₄ is solute.
Water is solvent.
Explanation:
Given data:
Mass of H₂SO₄ = 294.3 g
Volume of water = 250 mL
Which is solute = ?
Which is solvent = ?
What is molarity = ?
Solution:
Solute and solvent.
Solute is present in less quantity as compared to the solvent. It is always dissolved by the solvent. In given question water is present in large amount so it is solvent. While H₂SO₄ is solute.
If we convert the g of H₂SO₄ into volume,
d = m/v
1.83 g/cm³ = 294.3 g / v
v = 294.3 g/ 1.83 g/cm³
v = 160.82 cm³ or 160.82 mL
SO water is present in large amount.
Molarity:
Molarity = number of moles of solute / volume of solution in L
Volume of solution = 160.82 mL + 250 mL
Volume of solution = 410.82 mL (410.82 /1000 =0.411 L)
Number of moles of solute:
Number of moles = mass/ molar mass
Number of moles = 294.3 g/ 98.1 g/mol
Number of moles = 3 mol
Now we will determine the molarity:
Molarity = 3 mol / 0.411 L
Molarity =7.3 M
