Answer:
The angles between the vertices y'P0 and y'Q0 must be equal
α=β
Step-by-step explanation:
To demonstrate that each point of segment AB is equidistant from the end points P and Q, it is enough to take any point of segment AB and determine the angle formed between this point and points P and Q
According to the graph the angles generated by the vertices y'P0 and y'Q0 must be equal, and these are determined by the sine, cosine or tangent, we will take for example the tangent
tgα=y'/P = 5/-6 ⇒ α=atg(5/-6) ≅ -39,80° ∧ tgβ=(5/6) ⇒ β=atg(5/6) ≅ 39,80°
The negative sign indicates that the tangent is negative in that quadrant (2nd)
, finally α=β
