Answer:
Time after which it collide again is
[tex]T = 1.01 \times 10^{-8} s[/tex]
Explanation:
As we know that the neutral particle decays into two particles i.e. electron and positron
As we know that both particles are of same mass but opposite charge
So both particles will revolve in the circle in opposite sense
So both particles will collide again after one complete revolution
So the time period of revolution is given as
[tex]T = \frac{2\pi m}{qB}[/tex]
so we whave
[tex]T = \frac{2\pi(9.1 \times 10^{-31})}{(1.6 \times 10^{-19})(3.53 \times 10^{-3})}[/tex]
[tex]T = 1.01 \times 10^{-8} s[/tex]
