Probability that the total number rolled would be 1 , 2 , 3 is [tex]\frac{1}{6}[/tex] or 0.167 each .
Step-by-step explanation:
Here we have , a pair of 1-6 number generators is tossed once, . We need to find that what is the probability that the total number rolled would be..1?.... 2?.... 3?. Tossed once, and number of outcomes are { 1,2,3,4,5,6 } out of which we need to find probability that the total number rolled would be 1 , 2 , 3 .
Probability for 1: Number 1 will come out of 6 digits present there so,
[tex]Probability = \frac{favorable-outcomes}{total-outcomes}[/tex]
⇒ [tex]Probability = \frac{favorable-outcomes}{total-outcomes}[/tex]
⇒ [tex]Probability = \frac{1}{6}[/tex]
⇒ [tex]Probability = 0.167[/tex]
Probability for 2:Number 2 will come out of 6 digits present there so,
[tex]Probability = \frac{favorable-outcomes}{total-outcomes}[/tex]
⇒ [tex]Probability = \frac{favorable-outcomes}{total-outcomes}[/tex]
⇒ [tex]Probability = \frac{1}{6}[/tex]
⇒ [tex]Probability = 0.167[/tex]
Probability for 3:Number 3 will come out of 6 digits present there so,
[tex]Probability = \frac{favorable-outcomes}{total-outcomes}[/tex]
⇒ [tex]Probability = \frac{favorable-outcomes}{total-outcomes}[/tex]
⇒ [tex]Probability = \frac{1}{6}[/tex]
⇒ [tex]Probability = 0.167[/tex]
