Answer:
speed of the arrow as it leaves is 41.05 m/sec
Explanation:
We have given mass m = 0.285 kg
Average force F = 182 N
Distance traveled d = 1.32 m
We know that work done = force [tex]\times[/tex]distance
Sp work done = [tex]182\times 1.32=240.24J[/tex]
Now according to work energy theorem work done will be equal to kinetic energy
So [tex]\frac{1}{2}mv^2=240.24[/tex]
[tex]\frac{1}{2}\times 0.285\times v^2=240.24[/tex]
[tex]v^2=1685.89[/tex]
v = 41.05 m/sec
So speed of the arrow as it leaves is 41.05 m/sec
