Answer:
0.9772
Step-by-step explanation:
The machine in the factory fills bottles of ketchup with a mean of 16.1 oz and a standard deviation of 0.05 oz.
We want to find the probability that a bottle of ketchup contains less than 16 oz.
We find the z-score of x=16.1 using
[tex]z = \frac{x - \mu}{ \sigma} [/tex]
We substitute to get;
[tex]z = \frac{16.1 - 16}{0.05} = \frac{0.1}{0.05} = 2[/tex]
We read read the area corresponding to 2.0 on the standard normal distribution table to get:
P(X≤16.1)=0.9772
