Respuesta :
Answer:
156.1 rad/s = 24.8 rev/s
Explanation:
Torque = Momentum of inertial × radial acceleration = Iα
τ = 26.6 N.m
I = 0.162 kg.m²
26.6 = 0.162 × α
α = 164.2 rad/s²
Using equations of motion,
θ = 11.8 rev = 11.8 × 2π = 74.2 rad
w₀ = 0 rad/s (since the grindstone starts from rest)
w = ?
α = 164.2 rad/s²
w² = w₀² + 2(α)(θ)
w² = 0² + (2×164.2)(74.2)
w = 156.1 rad/s = 24.8 rev/s
Hope this Helps!!!
Answer:
Explanation:
wi = 0 rad/s (starts from rest)
Torque, T= 26.6 N.m
Moment of inertia, I = 0.162 kg.m2
Theta = 11.8 rev
Converting rev to rad,
1 rev = 2pi rad
11.8 rev × 2pi rad/1 rev
= 74.14 rad
Using the formula,
T = I × a
Where,
a = angular acceleration
a = 26.6/0.162
= 164.2 rad/s^2
Using equations of circular rmotion,
wf^2 = wi^2 + 2a × theta
= 0 + 2 × 164.2 × 74.14
= 12174.05
wf = sqrt(12174.05)
= 110.34 rad/s.
