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When 1.310 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00°C to 68.10°C. In a separate experiment, the heat capacity of the calorimeter is measured to be 9.84 kJ/K. The heat of reaction for the combustion of a mole of TiTi in this calorimeter is __________ kJ/mol.

Respuesta :

Answer:

the heat of reaction for the combustion of a mole of Ti n this calorimeter is 15478 KJ/mol.

Explanation:

Ti + O₂ ------> TiO₂

Heat produced from the combustion reaction = Heat gained by the calorimeter

Heat gained by the calorimeter = C ΔT

C = Heat capacity of the calorimeter = 9.84 KJ/K = 9840 J/K

ΔT = change in temperature = 68.10 - 25 = 43.10°C = 43.10 K (change in temperature is the same in the two units.

Heat gained by the calorimeter = (9840)(43.10) = 424,104 J = 424.1 KJ

This is equal to heat released on combustion of 1.310 g of Titanium.

Number of moles of 1.310 g of Titanium = (mass/molar mass) = (1.310/47.867) = 0.0274 mole.

0.0274 mole of Titanium released 424,104 J of heat on combustion,

1 mole of Titanium will release (424104×1/0.0274) J of heat on combustion.

Which is equal to 15,478,248.2 J = 15478 KJ/mol of heat.

Hence, the heat of reaction for the combustion of a mole of Ti n this calorimeter is 15478 KJ/mol.

Hope this Helps!!!

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