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Margie has 5 times as many nickels as quarters. She has a total of $2.00. Write a system of equations to represent the situation. Let n represent the number of nickels and q represent the number of quarters. Solve the system you wrote in part (a). Show your work. Interpret your solution in the context of the problem. I really do need the help

Respuesta :

calculista

Answer:

Margie has 20 nickel's coin and has 4 quarter's coin

Step-by-step explanation:

Let

x ---> the number of nickel's coin

y ----> the number of quarter's coin

Remember that

[tex]1\ nickel=\$0.05[/tex]

[tex]1\ quarter=\$0.25[/tex]

we know that

Margie has a total of $2.00

so

[tex]0.05x+0.25y=2.00[/tex] ----> equation A

Margie has 5 times as many nickels as quarters

so

[tex]x=5y[/tex] ----> equation B

substitute equation B in equation A

[tex]0.05(5y)+0.25y=2.00[/tex]

solve for y

Multiply by 100 both sides

[tex]25y+25y=200\\50y=200\\y=4[/tex]

Find the value of x

[tex]x=5(4)=20[/tex]

therefore

Margie has 20 nickel's coin and has 4 quarter's coin

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