a) 10 m/s
b) 25 m
Explanation:
a)
The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:
[tex]v=u+at[/tex]
where
u is the initial velocity
v is the final velocity
a is the acceleration
t is the time
For the body in this problem:
u = 0 (the body starts from rest)
[tex]a=2 m/s^2[/tex] is the acceleration
t = 5 s is the time
So, the final velocity is
[tex]v=0+(2)(5)=10 m/s[/tex]
b)
In this second part, we want to calculate the distance travelled by the body.
We can do it by using another suvat equation:
[tex]v^2-u^2=2as[/tex]
where
u is the initial velocity
v is the final velocity
a is the acceleration
s is the distance travelled
Here we have
u = 0 (the body starts from rest)
[tex]a=2 m/s^2[/tex] is the acceleration
v = 10 m/s is the final velocity
Solving for s,
[tex]s=\frac{10^2-0^2}{2(2)}=25 m[/tex]
