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580 nm light shines on a double slit with d=0.000125 m. What is the angle of the third dark interference minimum(m=3)?

Respuesta :

Answer:

0.665

Explanation:

use the last formula shown on the lesson manual on acellus and plug it in

The angle of the third dark interference is 0.665.

The wavelength λ = 580 nm

Distance d = 0.000125 m

Line number m = 3

What is the angle of the dark interference?

 To find the angle of third dark interference, the formula is,

                  sin θ = Line number × λ ÷ ( distance)

Substituting all the values,

              sin θ =  ( 3 × 580 × 10⁻⁹ ) ÷ ( 0.000125)

                    θ  = sin⁻¹ ( 0.0116 )

                    θ = 0.665

Learn more about the angle of interference,

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