Answer:
3485.63 pounds
Step-by-step explanation:
For cone shaped sand:
Height (h) = 3.5 ft
Diameter (d) = 6.5 ft
Therefore, radius (r) = 6.5/2= 3.25 ft
[tex]volume \: of \: sand \\ = \frac{1}{3} \pi {r}^{2} h \\ \\ = \frac{1}{3} \times \frac{22}{7} \times {(3.25)}^{2} \times 3.5\\ \\ = \frac{1}{3} \times 22 \times 10.5625 \times 0.5\\ \\ = \frac{1}{3} \times 11 \times 10.5625 \\ \\ = \frac{1}{3} \times 116.1875 \\ \\ = 38.7291667 \: {ft}^{3} \\ \\ \because \: 1 \: {ft}^{3} = 90 \: pounds \\ \\ \therefore \: 38.7291667 \: {ft}^{3} \\ = 38.7291667 \times 90 \ \\ = 3,485.625 \: pound \\ \approx \: 3485.63 \: pounds[/tex]
Hence, weight of sand is 3485.63 pounds.
