Answer:
Speed of the ball after it strike with bottle is 10 m/s
Explanation:
As we know that there is no external force on the system of bottle + ball
So we can use momentum conservation for this system
So we will have
[tex]mv = mv_1 + Mv_2[/tex]
so we will have
[tex]0.50(20) = 0.50 v_1 + 0.20 (25)[/tex]
[tex]10 = 0.50 v_1 + 5[/tex]
so we have
[tex]5 = 0.50 v_1[/tex]
[tex]v_1 = 10 m/s[/tex]